How Can I Move Selected Option In Multiselect Up And Down By Buttons Using Jquery?

I have select 123<

Solution 1:

Update: Fixed code for multiple options selected, based on @patrick dw's suggestion.

$(document).ready(function(){
    $('input[type="button"]').click(function(){
        var$op = $('#select2 option:selected'),
            $this = $(this);
        if($op.length){
            ($this.val() == 'Up') ? 
                $op.first().prev().before($op) : 
                $op.last().next().after($op);
        }
    });
});

Test it here »

No need to use inline onclick="" event listeners. jQuery takes full control of separating presentation from functionality.

Solution 2:

if you do not use jquery

function moveUp(){
    varselect = document.getElementById("columnOrder");
    var options = select && select.options;
    var selected = [];

    for (var i = 0, iLen = options.length; i < iLen; i++) {
        if (options[i].selected) {
            selected.push(options[i]);
        }
    }

    for (i = 0, iLen = selected.length; i < iLen; i++) {
        var index = selected[i].index;

        if(index == 0){
            break;
        }

        var temp = selected[i].text;
        selected[i].text = options[index - 1].text;
        options[index - 1].text = temp;

        temp = selected[i].value;
        selected[i].value = options[index - 1].value;
        options[index - 1].value = temp;

        selected[i].selected = false;
        options[index - 1].selected = true;
    }
}

function moveDown(){
    varselect = document.getElementById("columnOrder");
    var options = select && select.options;
    var selected = [];

    for (var i = 0, iLen = options.length; i < iLen; i++) {
        if (options[i].selected) {
            selected.push(options[i]);
        }
    }

    for (i = selected.length - 1, iLen = 0; i >= iLen; i--) {
        var index = selected[i].index;

        if(index == (options.length - 1)){
            break;
        }

        var temp = selected[i].text;
        selected[i].text = options[index + 1].text;
        options[index + 1].text = temp;

        temp = selected[i].value;
        selected[i].value = options[index + 1].value;
        options[index + 1].value = temp;

        selected[i].selected = false;
        options[index + 1].selected = true;
    }
}

Solution 3:

functionup() {
    var selected = $("#select2").find(":selected");
    var before = selected.prev();
    if (before.length > 0)
        selected.detach().insertBefore(before);
}

functiondown() {
    var selected = $("#select2").find(":selected");
    var next = selected.next();
    if (next.length > 0)
        selected.detach().insertAfter(next);
}

Solution 4:

I created a jquery plugin for this: https://github.com/UziTech/jquery.moveSelected.js

usage:

$("button#up").click(function(){
  $("select").moveSelectedUp();
});
$("button#down").click(function(){
  $("select").moveSelectedDown();
});

http://jsfiddle.net/UziTech/qr5qfhgg/

Solution 5:

here is the same idea as the previously-posted non-jquery example, but with some strategic code re-use. My need was to have the buttons always operate on the same select element, named "cols". You could put "sel" as a parameter of the moveUp() and moveDown() functions if you want something more generic.

functionmoveUp() {
    var sel = document.getElementById("cols");
    var i1=0, i2=1;
    while (i2 < sel.options.length) {
        swapIf(sel,i1++,i2++);
    }
}
functionmoveDown() {
    var sel = document.getElementById("cols");
    var i1=sel.options.length-1, i2=i1-1;
    while (i1 > 0) {
        swapIf(sel,i1--,i2--);
    }
}
var swapVar = '';
functionswapIf(sel,i1,i2) {
    if ( ! sel[i1].selected && sel[i2].selected) {
        swapVar = sel[i2].text;
        sel[i2].text = sel[i1].text;
        sel[i1].text = swapVar;
        swapVar = sel[i2].value;
        sel[i2].value = sel[i1].value;
        sel[i1].value = swapVar;
        sel[i1].selected = true;
        sel[i2].selected = false;
    }
}

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